Question 978184
A=Ao(1+r)^t, where t=number of 10 minute intervals
A/Ao=2=(1+r)^t
ln of both sides
0.693=t(ln(1+r)
t=1
0.6931=ln(1+r)
2=(1+r); r=1

80000=Ao(2)^11
ln 80000=ln Ao+11 ln(2)
11.2898=ln Ao + 7.623
3.6667=ln Ao
Take e of both sides.
e=39.12 or 39, initially

39[(2)^11]=79872, and with rounding, that is 80000

after 3 hours, t=18
39*2^18=
10,223,616.  Note, must round down to 39 first, since can't have a fractional bacterium.