Question 978037
we are given the polar coordinates of two vectors A and B, the first step is to convert them into Cartesian coordinates
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measure angle direction from x axis, 174 = -6 and 388 = 28
Vector A
x = r * cos(theta) = 352 * cos(-6) =  350.07170717 approx  350.07
y = r * sin(theta) = 352 * sin(-6) =  -36.79401907 approx  -36.79
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Vector B
x = r * cos(theta) = 276 * cos(28) = 243.693535629 approx 243.69
y = r * sin(theta) = 276 * sin(28) = 129.574151329 approx 129.57
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now add them
(350.07, -36.79) + (243.69, 129.57) = (593.76, 92.78)
magnitude(C) = square root(593.76^2 + 92.78^2)
C = 600.965112132 approx 600.97
tan (thetaC) = 92.78 / 593.76 = 0.156258421
inverse tan (0.156258421) = 8.881130134 approx 9 degrees
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therefore,
vector sum is (593.76, 92.78)
vector component magnitude is 600.97 and direction is 9 degrees