Question 978043
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  h(x)\ =\ 4x^2\ +\ 3x\ +\ 6]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  h(x)\ =\ 4\left(x^2\ +\ \frac{3}{4}x\right)\ +\ 6]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  h(x)\ =\ 4\left(x^2\ +\ \frac{3}{4}x\ +\ \left(\frac{3}{8}\right)^2\right)\ +\ 6\ -\ 4\left(\frac{3}{8}\right)^2]


You should be able to factor the perfect square trinomial and do the clean up arithmetic yourself.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \