Question 978041
Most important goal is solve for x and y.


{{{x(3-x)=1}}}
{{{-x^2+3x-1=0}}}
{{{x^2-3x+1=0}}}


{{{highlight(x=(3-sqrt(5))/2)}}}
and then {{{y=3-(3-sqrt(5))/2=6/2-3/2+sqrt(5)/2=highlight(y=3/2+sqrt(5)/2)}}}
which is only one of the two x y pairs.



Evaluating the two requested expressions is a bunch of arithmetic.
(You might want to use Binomial Theorem.)