Question 977750
{{{((x+1)^3 (3x-5) - (x+1)^2 (8x+3))/(x-4)(x+1)^3}}}
Cancel (x+1)^2
= {{{((x+1) (3x-5) - (8x+3))/(x-4)(x+1)}}}
= {{{((3x^2 - 2x - 5) - (8x+3))/(x-4)(x+1)}}}
= {{{(3x^2 - 10x - 8)/(x-4)(x+1)}}}
= {{{((3x+2)*(x -4))/(x-4)(x+1)}}}
= {{{(3x+2)/(x+1)}}}