Question 977751
With the table as given you can only get two decimal place accuracy.
You can read a value for -0.51(0.30503) and for -0.52 (0.30153). 
You can also interpolate a linear value (although the normal distribution curve is not linear).
Assume their is a straight line relationship, so find the line between (-0.51,0.30503) and (-0.52,0.30153)
Slope: {{{m=(0.30153-0.30503)/(-0.52+0.51)=0.35}}}
{{{P-0.30503=0.35(z-(-0.51))}}}
{{{P-0.30503=0.35z+0.1785}}}
{{{P=0.35z+0.48353}}}
So then, when {{{z=-0.5147}}}
{{{P=0.35(-0.5147)+0.48353}}}
{{{P=0.303385}}}
{{{highlight(P=0.3034)}}}