<PRE><B>Question 977634</B>
Find the x intercepts of the parabola with vertex -1,-108 and y intercept 0,-105
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vertex form:: (x-h)^2 = 4p(y-k)
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h = -1 ; k = -108
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(x+1)^2 = 4p(y+108)
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Using (0,-105) solve for &quot;p&quot;::
1 = 4p(3)
p = 1/12
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Equation:
(x+1)^2 = (1/3)(y+108)
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Find the x-intercepts::
Let y = 0, then
(x+1)^2 = (1/3)(108)
(x+1)^2 = 36
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x+1 = 6 or x+1 = -6
x = 5 or x = -7
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Cheers,
Stan H.
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