Question 977566
<pre>
{{{ ln( 5 x + 3 )}}}{{{""=""}}}{{{5}}}

Use the fact that equal powers of the same base are equal,
using base e:

{{{e^(ln( 5 x + 3) )}}}{{{""=""}}}{{{e^5}}}

Use the fact that {{{e^(ln(A))=A}}}

{{{5x+3}}}{{{""=""}}}{{{e^5}}}

{{{5x}}}{{{""=""}}}{{{e^5-3}}}

{{{x}}}{{{""=""}}}{{{(e^5-3)/5}}}

x is approximately 29.08263182

Edwin</pre>