Question 977367
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A(C)\ =\ \frac{\left(20\ -\ C\right)^2}{16}\ +\ \frac{C^2}{16\pi}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\text{d}A}{\text{d}C}\ =\ \frac{(\pi\ +\ 1)C\ -\ 20\pi}{8}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\text{d}^2A}{\text{d}C^2}\ =\ \frac{\pi\ +\ 1}{8\pi}]


The steps I left out are trivial; you can finish it for yourself.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \