Question 976751
{{{log(x^2) = x/25}}}
=> {{{2*log(x) =x/25}}}
=> {{{log(x) = x/50}}}
.
=> {{{10^(x/50) = x}}}
By suitably assuming x as mulitples of 50, and cross-checking,
we get
x=100

Check:
RHS = 100
.
LHS ={{{10^(100/50)}}}
={{{10^2}}}
=100 = RHS