Question 977443
Perpendicular lines have slopes that are negative reciprocals.
{{{m[p]*(1/5)=-1}}}
{{{m[p]=-5}}}
So then,
{{{y-(-3)=-5(x-2)}}}
{{{y+3=-5x+10}}}
{{{y=-5x+7}}}
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*[illustration dd10.JPG].