Question 975634
{{{cos^2(theta)+(-5/13)^2=1}}}
{{{cos^2(theta)=1-25/169}}}
{{{cos^2(theta)=144/169}}}
{{{cos(theta)=12/13}}} since in Q4 cosine is positive.
{{{tan(theta)=sin(theta)/cos(theta)}}}
{{{tan(theta)=-(5/13)/(12/13)}}}
{{{highlight(tan(theta)=-5/12)}}}