Question 977420
 Using graphing technology graph x^4-7x^3+12x^2+4x-12. Identify for which values of x the graph is increasing.
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f'(x) = 4x^3 -21x^2 + 24x + 4 
Solve:: 4x^3-21x^2 + 24x+4 > 0
{{{graph(400,400,-10,10,-10,10,x^4-7x^3+12x^2+4x-12)}}}
Ans: increasing from x = 0.1472 to x = 2 and also when x > 3.5
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Cheers,
Stan H.
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A. X:-3 to x:-2
B.x:-2 to x:-1
C. X:1 to x:2
D. X:2 to x:3