Question 83392
Given a line:
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{{{y = (2/3)x+1}}}
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This is in the slope-intercept form:
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{{{y = mx + b}}}
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in which m (the multiplier of x) is the slope of the line and b is the value of y at the 
point the graph of the line crosses the y-axis.
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By comparing the slope intercept form with the given equation you can see that in the given
equation {{{2/3}}} is the slope because it is the multiplier of x.
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Any line that is parallel to the graph of {{{y = (2/3)x + 1}}} must have the same slope
as the graph. So, in the slope intercept form, the line L will have the equation:
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{{{y = (2/3)x + b}}} where b is the y-axis intercept.  The problem tells you that the
value of y on the y-axis is -3.  Substituting this for b in the equation results in the
equation for L becoming:
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{{{y = (2/3)x - 3}}}
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and this is the answer to the problem. Line L is defined by the equation:
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{{{y = (2/3)x -3}}}
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Hope this helps you to understand the concept of parallel graphs ... they will have the
same slope, but the y-intercepts will be different.