Question 977353
 a= 13 , b= 14 c=14 ft
area of triangle ={{{sqrt(s(s-a)(s-b)(s-c))}}}
         where s ={{{(a+b+c)/2}}}
          s= {{{ ( 13+14+14)/2}}}
             = {{{41/2}}}
=20.5
area={{{sqrt(s(s-a)(s-b)(s-c))}}}
    ={{{20.5*(20.5-13)(20.5-14)(20.5-14)}}}
   ={{{20.5*7.5*6.5*6.5}}}
  =80.597 sq.ft
area = 80.597 square ft