Question 977348
Equal degree, numerator and denominator; horizontal asymptote y=1.


{{{f(x)=((x+2)(x-2))/((x-5)(x+3))}}}


Zeros for x=-2 and x=2.
Vertical asymptotes x=-3 and x=5.


You can figure how the branches go as positive or negative in each interval.
You do that!



{{{graph(300,300,-10,10,-10,10,(x^2-4)/(x^2-2x-15))}}}