Question 977239
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Solve *[tex \Large x\ -\ y\ =\ 5] for *[tex \Large y].  Substitute into *[tex \Large xy\ =\ 84].  Solve the resulting quadratic for both possible values for *[tex \Large x].  Solve *[tex \Large x\ -\ y\ =\ 5] for both possible values for *[tex \Large y].  Substitute each of your value pairs into *[tex \Large x^3\ -\ y^3] and do your arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \