Question 11662
It's not a problem if you remember: you do all grouped operations first (that's operations in parentheses), then you do all multiplies and divides, then all adds and subtracts.
There are no groups in 2a+3b+c/2d. So you do the multiplies followed by the  divide.
2 x 2 + 3 x 0 + 3 / 2 x (-5)  [substituting 2 for a, 0 for b, 3 for c, and -5 for d]
{{{4 + 0 + (3/2) (-5) = 4 + 0 + (-15/2)=8/2 - 15/2=-7/2}}}
Or, -3 1/2