Question 977182
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Right triangle.  One leg is 5, one leg is *[tex \Large x] and the hypotenuse is *[tex \Large x\ +\ 1].  According to our good old Greek friend, Pythagoras,


 *[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ +\ 1)^2\ =\ 5^2\ +\ x^2]


Solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \