Question 977136
This is not going to be yet the complete solution, but is just part of the steps to get to it:


First equation is {{{log(8(xy))=3}}}


{{{log(2,(xy))/log(2,8)=3}}}


{{{log(2,(xy))/log(2,(2^3))=3}}}


{{{log(2,(xy))/3=3}}}


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{{{log(2,(xy))=9}}}-----In this form, the equation will be easier to relate to the other given equation.


You should work through that on your own including the second given equation in the system of equations.
You should be able to form through the steps something like,
{{{(log(2,x)-3)(log(2,x)-6)=0}}}
which means that either {{{log(2,x)=3}}}  OR  {{{log(2,x)=6}}}.


The values are turned around for dealing logs of y.


You should then be able to finish find x and y.
One of them is 2^3 and the other is 2^6.