Question 977124
Let the Son's present age=x
Let the fathers present age =y
we get the first equation x+y=60......equation 1
Go back 2 years
Sons age=x-2
Father's age=y-2
we get 3(x-2)=y-2
giving 3x-6=y-2
3x-y=-2+6
3x-y=4.......equation 2
finally
x+y=60
3x-y=4
adding both equations
we get 4x=64
x=64/4=16
So present age of son=16
present age of Reyes(father)=60-16=44
So when the son was born father's age=44-16=28