Question 977109
How do you solve this problem? 
assuming x>0 and y>0, if 16y^2+40xy+25x^2=36, what is the value of 3(4y+5x)?
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16y^2+40xy+25x^2=36
(4y+5x)^2=36
4y+5x=√36=±6
3(4y+5x)=±18