Question 976561
{{{P(0)=C(10,0)(0.5)^0(0.5)^10}}}
{{{P(0)=(0.5)^10}}}
{{{P(1)=C(10,1)(0.5)^1(0.5)^9}}}
{{{P(1)=10(0.5)^10}}}
{{{P(2)=C(10,2)(0.5)^2(0.5)^8}}}
{{{P(2)=45(0.5)^10}}}
{{{P(3)=C(10,3)(0.5)^3(0.5)^7}}}
{{{P(3)=120(0.5)^10}}}
So then,
{{{P=P(0)+P(1)+P(2)+P(3)}}}
{{{P=(1+10+45+120)(0.5)^10}}}
{{{P=176/2^10}}}
{{{P=11/2^6}}}
{{{P=11/64}}}