Question 977030
In a three digit number unit's digit, ten's digit and hundred's are in the ratio of 1:2:3. If the difference in the original number and the number obtained by reversing the digit is 594 find the number?
***
let u=units digit
let t=tens digit
let h=hundredth digit
..
(100h+10t+u)-(100u+10t+h)=594
100h+10t+u-100u-10t-h)=594
99h-99u=594
h=3u
99*3u-99u=594
297u-99u=594
198u=594
u=3
h=3u=9
t=2u=6
..
check:
100h+10t+u=900+60+3=963
100u+10t+h=300+60+9=369
difference: 963-369=594