Question 976931
The sample mean must be within 2 of the population mean.
I will do one side.
z=x bar-mu/sd/sqrt (50);; z= (98-100)*sqrt (50)/sd.   I am inverting the denominator and multiplying.

z=(-2)*7.0710/13= -1.0878
I want the probability z will be within -1.0878 and +1.0878.

z=0.7233.  This makes sense, because 68% are within 1 sd.


The probability one person will be more than 2 points away from the population mean is high, about 87%.  With a sample of 50, however, those who are on one side will be counterbalance by those on the other.