Question 976910
a+b+c=17
b=1+a+c
100a+10b+c-100c-10b-a=396
99a-99c=396
a-c=4
a=c+4
b=1+a+c
b=1+c+4+c
b=5+2c
a+b+c=17

(c+4)+[5+2c]+c=17
4c+9=17
4c=8
c=2
a=6
b=9
number is 692
check
692-296=396
ok