Question 976853
I have an unsimplified equation and need to simplify it then solve for x:

{{{( 3sqrt(2) - x )/( sqrt(x) ) = sqrt(2x)/ ( sqrt(2) - x ) }}}

so if I simplify using cross multiply I should have?:

{{{6 - sqrt(2)x - 3sqrt(2)x + x^2 = sqrt(2)x}}}

{{{x^2 - 5sqrt(2)x + 6 = 0}}}

I'm new to doing this with square roots all involved, did I go about this right?
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Looks right.  Solve for x.
{{{x^2 - 5sqrt(2)x + 6 = 0}}}
{{{x^2 + 6 = 5sqrt(2)x}}}
Square both sides.
{{{x^4 + 12x^2 + 36 = 50x^2}}}
{{{x^4 - 38x^2 + 36 = 0}}}
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Sub u for x^2
{{{u^2 - 38u + 36 = 0}}}
*[invoke solve_quadratic_equation 1,-38,36]
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x^2 = answers shown
Find the sq roots.
Check for extraneous solutions.