Question 976804
Assume that the random variable X is normally distributed, with mean 80 and standard deviation 16. Compute the probability P(X<100)
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z(100) = (100-80)/16 = 5/4
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P(x < 100) = P(z < 5/4) = normalcdf(-100,5/4) = 0.8944
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Cheers,
Stan H.
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