Question 976787
3 even numbers can be written as

{{{(2n)+(2n+2)+(2n+4)}}}


{{{2n+(1/2)(2n+2)+(1/4)(2n+4)=(4n-20)}}}


{{{2n+(n+1)+(1/4)(2n+4)=(4n-20)}}}


{{{(3n+1)+(1/4)(2n+4)=(4n-20)}}}


multiply both sides by 2 to get rid of that 1/4


{{{(6n+2)+(n+2)=(8n-40)}}}

{{{7n+4=8n-40}}}

{{{0=n-44}}}

{{{n=44}}}

The numbers are

88,90,92

the sum of the first (88), one half of the second (45), and one fourth of the third (23) (total 156) is twenty less than twice the first (176-20)