Question 976726
{{{ n(t) = 79*e^( .015t ) }}}
{{{ t }}} is years since 1992
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To show the year 1992, set
{{{ t = 0 }}}
Any number to the zero power
is {{{ 1 }}}
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{{{ n(0) = 79*e^0 }}}
{{{ n(0) = 79 }}}
The rat population in 1992 was 79 million
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2009 is {{{ 17 }}} years since 1992
{{{ n(17) = 79*e^( .015*17 ) }}}
{{{ n(17) = 79*e^.255 }}}
{{{ n(17) = 79*1.2905 }}}
{{{ n(17) = 101.95 }}}
The rat population in 2009 will be 101,949,500