Question 976702

{{{-7y=6}}};if {{{y=13}}}, we have {{{-7*13=6}}}=> {{{-91=6}}} which is {{{not}}} {{{true}}} ({{{-91<>6}}} )


{{{3a-1=4}}};if {{{a=(5/3)}}} we have {{{cross(3)(5/cross(3))-1=4}}}=>{{{5-1=4}}}
=>{{{4=4}}} which is {{{true}}}
   
      
{{{2(b-3) = -2 (2-3b)}}}; if {{{b=-4}}} we have {{{2(-4-3) = -2 (2-3(-4))}}}=>{{{2(-7) = -2 (2+12)}}}=>{{{-14 = -2 (14)}}}=>{{{-14 = -28}}} which is {{{not}}} {{{true}}}


{{{5x-2=0/8}}}; =>{{{5x-2=0}}}

if {{{x=(2/5)}}} we have {{{cross(5)(2/cross(5))-2=0}}}=>{{{2-2=0}}}=>{{{0=0}}} which is {{{true}}}

      
{{{6(t+2)=3(7-t)}}}; if {{{t=-1}}} we have {{{6(-1+2)=3(7-(-1))}}}=>{{{6(1)=3(7+1)}}}=>{{{6=3(8)}}}=>{{{6=24}}} which is {{{not}}} {{{true}}}