Question 976555

The width (w) of a rectangle is two less than 1/3 of its length (l). If  the perimeter is 116 cm. identify the equation of the problem
<pre>Let length be L, and width, W
Then W = {{{L/3 - 2}}}
2(L + W) = perimeter
2(L + W) = 116
2(L + W) = 2(58)
L + W = 58
{{{L + L/3 - 2 = 58}}} ------ Substituting {{{L/3 - 2}}} for width
{{{highlight_green(L + L/3 = 60)}}} ------ Required equation