Question 976554
let two consecutive integers be x, x+1
  x+(x+1)+19 = 58
    2x+1 +19 = 58
      2x+20 = 58
      subtract 20 on both sides
     2x+20-20 = 58-20
 2x = 38 
  divide with 2 on both sides
 {{{ 2x/2 = 38/2}}}
  {{{ x= 19}}}
    x= 19 
x+1 = 19+1 = 20
 The consecutive integers   =  19,20