Question 976502
A party rental company has chairs and tables for rent. The total cost to rent 
4 chairs and 8 tables is $57
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The total cost to rent 2 chairs and 3 tables is $22. 
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What is the cost to rent each chair and each table?
Equations::
4c + 8t = 57
2c + 3t = 22
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Modify for elimination:
4c + 8t = 57
4c + 6t = 44
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Subtract and solve for "t":
2t = 13
t = $6.50 (cost of one table)
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Solve for "c":
2c + 3t = 22
2c + 19.5 = 22
2c = 2.5
c = $1.25 (cost of one chair)
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Cheers,
Stan H. 
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