Question 976419
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First integer: *[tex \Large x]; second integer *[tex \Large x\ +\ 1]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ (x\ +\ 1)^2\ =\ 2(x\ +\ 1)^2\ -\ 31]


Solve for *[tex \Large x], then calculate *[tex \Large x\ +\ 1]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \