Question 976442
The dimensions are  (5w+32)cm by (5w-32)cm .  I don't know what is added.

The area as it stands is 25w^2-1024.  If w=10, the area is 2500-1024=1476, an 82X18 rectangle

If you add 10 cm, the lot is (5w+42)(5w-22)=25w^2+100w-964.  If w=10, area is 3500-964=2536, a 92X28 rectangle.  It is quadratic, however, and not simply linear, like the perimeter.

Areas increase as the square, but it is more complicated in a rectangle because of internal products.  Double the side length of a square and you increase the area 4 times.  Triple it and you increase the area 9 times.  With a rectangle, it is not that simple, but the This is basically how you do these problems.  Again, without knowing what is added, I can't tell.



Example:
2*5 lot =10 square units.
add x to each.  
(2+x)(5+x)=10 + 7x +x^2

if x =1, the lot's new area is 3*6=18
x^2+7x+10=18.