Question 83306
Given the vertex is (0,0) and the focus is (0,2)

Now d = distance between the focus and the vertex

     = sqrt (0^2 + 2^2)

    = sqrt(4)

    = 2

So a = 1/4d

    = 1/8

Vertex (h.k) = (0,0)

So equation of the parabola is y = a(x-h)^2 + k

                                 = 1/8 [x-0]^2 + 0

                                 = 1/8 [x^2]

Thus the required equation is x^2 = 8y