Question 976395

Martina has {{{x}}}, 
Eric has {{{y}}}, and 
Jose has {{{z}}}

they have a total of ${{{x+y+z=77}}} in their wallets

 Eric has ${{{9}}} less than Martina: ${{{y=x-9}}}
Jose has {{{2}}} times what Eric has:${{{z=2y=2(x-9)}}}

 How much do they have in their wallets? 

${{{x+y+z=77}}}.... substitute {{{y}}} and {{{z}}}

${{{x+(x-9)+2(x-9)=77}}}.....solve for {{{x}}}

${{{x+x-9+2x-18=77}}}

${{{4x-27=77}}}

${{{4x=77+27}}}

${{{4x=104}}}

${{{x=104/4}}}

${{{x=26}}}

now find {{{y}}}

 ${{{y=x-9}}}
 ${{{y=26-9}}}
 ${{{y=17}}}

and {{{z}}}

${{{z=2y}}}

${{{z=2*17}}}

${{{z=34}}}

so, Martina has ${{{26}}}, Eric has ${{{17}}}, and Jose has ${{{34}}}