Question 976383
I'm assuming the original is {{{f(x) = 1/(x+2)}}}



The idea is to first replace f(x) with y. Then swap x and y. Finally, solve for y.



{{{f(x)= 1/(x+2)}}}
{{{y = 1/(x+2)}}}
{{{x = 1/(y+2)}}}
{{{x(y+2) = 1}}}
{{{xy+2x = 1}}}
{{{xy = -2x+1}}}
{{{y = (-2x+1)/x}}}



So the inverse function is *[Tex \LARGE f^{-1}(x) = \frac{-2x+1}{x}]


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