Question 976363
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The length is twice the width, so *[tex \Large l\ =\ 2w]


The height is 10 greater than the length, so *[tex \Large h\ =\ l\ +\ 10\ =\ 2w\ +\ 10]


Substitute in *[tex \Large V\ =\ lwh]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ V(w)\ =\ (2w)(w)(2w\ +\ 10)]


Simplify:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ V(w)\ =\ 2w^2(2w\ +\ 10)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ V(w)\ =\ 4w^3\ +\ 20w^2]


Now all you have to do is the arithmetic to evaluate


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ V(12)]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \