Question 976281
Find the value of k for which a-3b is a factor of a^4-7(a^2)(b^2)+kb^4. 
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3b)....1....0....7b^2....0....kb^2
-------1....3b...9b^2....27b^3...|kb^2+27b^3
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Solve:: kb^2+27b^3 = 0
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k = -27b
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Cheers,
Stan H.
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