Question 976207
One of the numbers has to be even.  Three odd numbers can't equal an even number.

we'll call that x.

We need two odd numbers whose sum is even and is 30-x

let one number be y, the other z

y+z+30-x=30.  Therefore, x=y+z

There are multiple solutions:  13,11,6;  15,13,2 etc.
Consecutive numbers (3) that add to 30 have 10 as the average, so they are 8.10,12 (even) or 9,10,11 (any).