Question 976199

{{{f(x) = (1)/(x+10) }}}

to find inverse  {{{f^(-1)(x)}}}, first recall that {{{f(x) =y}}}; so, substitute it in {{{f(x) = (1)/(x+10) }}}

{{{y = (1)/(x+10) }}} ...now swap {{{x}}} and {{{y}}}

{{{x = (1)/(y+10) }}}....solve for {{{y}}}

{{{x*(y+10)  = 1}}}

{{{y+10  = 1/x}}}

{{{y = 1/x-10}}}

so, your inverse is:

 {{{f^(-1)(x) = 1/x-10}}}


here is a graph:

{{{ graph( 600, 600, -10, 10, -10, 10, 1/(x+10), 1/x-10) }}}