Question 976195
{{{d/dx = x/(abs(x))}}}

 expanded equations of  {{{(abs(x))}}} is {{{x}}} and {{{-x}}}

{{{d/dx = x/x=1}}} or {{{d/dx = x/(-x)=-1}}}

so, 

domain: { {{{x}}} element {{{R}}} : {{{x<>0}}} }

range:{ {{{y}}} element {{{R}}} : {{{y = 1}}} or {{{y=-1}}} }