Question 976119
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The sum of the interior angles of any polygon with *[tex \Large n] vertices is *[tex \Large 180^{\circ}\left(n\ -\ 2\right)]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \