Question 976021
{{{system(log((8^n))= 1/2p, log((2^(2n)))=q, q-p=4)}}}, base was not indicated.


{{{system(n*log((8))=1/(2p),2n*log((2))=q,q-p=4)}}}


{{{system(3n*log((2))=1/(2p),q=2n*log((2)),q-p=4)}}}


{{{system(6n*log((2))=1/p,q=2n*log((2)),q-p=4)}}}


{{{system(p=-6n*log((2)),q=2n*log((2)),q-p=4)}}}




Substitute for p and q in the last equation, "4".


{{{2n*log((2))+6n*log((2))=4}}}


{{{n(2*log((2))+6*log((2)))=4}}}


{{{n(8*log((2)))=4}}}


{{{n*2*log((2))=1}}}


{{{highlight(n=1/(2*log((2))))}}}