Question 975979
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Let *[tex \Large x] represent the amount invested at 12%.  Then *[tex \Large 0.12x] is the annual return on the *[tex \Large 12%] investment.  If *[tex \Large x] is the portion of $170,000 that was invested at *[tex \Large 12%], then the amount invested at 5% must be *[tex \Large $170,000\ - x] and the annual return is *[tex \Large 0.05(170000\ -\ x)].  The two returns must sum to the desired annual income realization:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  0.12x\ +\ 0.05(170000\ -\ x)\ =\ 16900]


Solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \