Question 83242
<pre><font size = 5><b>
A 12-foot guy wire is attached to a 
telephone pole 10.5 ft from the top 
of the pole. If the wire forms a 52 
degree angle with the ground, how 
high is the telephone pole?


{{{drawing(600,330,-20,20,-2,20,

   line(-7.388,0,0,0), line(0,0,0,17.956), line(-7.388,0,0,9.456),

     locate(1,4.5,x), locate(1,14.7,"10.5'"), locate(-6.38,1.3,"52°")   
     locate(-6,5.5,"12'")            
        )}}}
                opposite
   sin(52°) = ------------
               hypotenuse

                x
   sin(52°) = ----
               12

Multiply both sides by 12

12 sin(52°) = x

9.456129043 = x

Total height of pole = 9.456129043 + 10.5 = 19.95612904

So you'd round that off to about 20 feet.

Edwin</pre>