Question 975837
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You left out a sign.


Presuming you meant 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ x^3\ -\ 6x^2\ +\ 9x]


Factor out *[tex \Large x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ x\left(x^2\ -\ 6x\ +\ 9\right)]


Now all that you need to do is factor the perfect square quadratic trinomial so that you have three factors.  Set each factor equal to zero and solve each equation for *[tex \Large x]


Or if you meant


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ x^3\ +\ 6x^2\ +\ 9x]


then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ x\left(x^2\ +\ 6x\ +\ 9\right)]


You still have a perfect square trinomial to factor.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \