Question 975804
Jessie recently drove to visit her parents who live 540 miles away. On her way there her average speed was 11 miles per hour faster than on her way home (she ran into some bad weather). If Jessie spent a total of 18 hours driving, find the two rates
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let x=speed on the way home
x+11=speed on the way to visit her parents
travel time=distance/speed
{{{540/x+540/(x+11)=18}}}
lcd: x(x+11).
..

540(x+11)+540x=18(x^2+11x)
540x+5940+540x=18x^2+198x
18x^2-882x-5940=0
divide by 18:
x^2-49x-330=0
(x+6)(x-55)=0
x=55
x+11=66
speed on the way home=55 mph
speed on the way to visit her parents = 66 mph